(3y-20)+(4y+4)=180

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Solution for (3y-20)+(4y+4)=180 equation: 



(3y-20)+(4y+4)=180

We move all terms to the left:

(3y-20)+(4y+4)-(180)=0

We get rid of parentheses

3y+4y-20+4-180=0

We add all the numbers together, and all the variables

7y-196=0

We move all terms containing y to the left, all other terms to the right

7y=196

y=196/7

y=28

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