(3y-28)/7=y/3

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Solution for (3y-28)/7=y/3 equation: 


y in (-oo:+oo)

(3*y-28)/7 = y/3 // - y/3

(3*y-28)/7-(y/3) = 0

(3*y-28)/7-y/3 = 0

(3*(3*y-28))/(3*7)+(7*(-y))/(3*7) = 0

3*(3*y-28)+7*(-y) = 0

2*y-84 = 0

(2*y-84)/(3*7) = 0

(2*y-84)/(3*7) = 0 // * 3*7

2*y-84 = 0

2*y-84 = 0 // + 84

2*y = 84 // : 2

y = 84/2

y = 42

y = 42

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