(3y-3)(2y+2)=58

Solution for (3y-3)(2y+2)=58 equation:

Simplifying
(3y + -3)(2y + 2) = 58

Reorder the terms:
(-3 + 3y)(2y + 2) = 58

Reorder the terms:
(-3 + 3y)(2 + 2y) = 58

Multiply (-3 + 3y) * (2 + 2y)
(-3(2 + 2y) + 3y * (2 + 2y)) = 58
((2 * -3 + 2y * -3) + 3y * (2 + 2y)) = 58
((-6 + -6y) + 3y * (2 + 2y)) = 58
(-6 + -6y + (2 * 3y + 2y * 3y)) = 58
(-6 + -6y + (6y + 6y2)) = 58

Combine like terms: -6y + 6y = 0
(-6 + 0 + 6y2) = 58
(-6 + 6y2) = 58

Solving
-6 + 6y2 = 58

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 6y2 = 58 + 6

Combine like terms: -6 + 6 = 0
0 + 6y2 = 58 + 6
6y2 = 58 + 6

Combine like terms: 58 + 6 = 64
6y2 = 64

Divide each side by '6'.
y2 = 10.66666667

Simplifying
y2 = 10.66666667

Take the square root of each side:
y = {-3.265986324, 3.265986324}