(3y-3)+(2y-2)=10

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Solution for (3y-3)+(2y-2)=10 equation: 



(3y-3)+(2y-2)=10

We move all terms to the left:

(3y-3)+(2y-2)-(10)=0

We get rid of parentheses

3y+2y-3-2-10=0

We add all the numbers together, and all the variables

5y-15=0

We move all terms containing y to the left, all other terms to the right

5y=15

y=15/5

y=3

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