(3y-3)+(y-2)+(2y)+(4y+5)=360

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Solution for (3y-3)+(y-2)+(2y)+(4y+5)=360 equation: 



(3y-3)+(y-2)+(2y)+(4y+5)=360

We move all terms to the left:

(3y-3)+(y-2)+(2y)+(4y+5)-(360)=0

We add all the numbers together, and all the variables

2y+(3y-3)+(y-2)+(4y+5)-360=0

We get rid of parentheses

2y+3y+y+4y-3-2+5-360=0

We add all the numbers together, and all the variables

10y-360=0

We move all terms containing y to the left, all other terms to the right

10y=360

y=360/10

y=36

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