(3y-4)(y+2)(y+1)=3y+5y-6y-8

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Solution for (3y-4)(y+2)(y+1)=3y+5y-6y-8 equation: 



(3y-4)(y+2)(y+1)=3y+5y-6y-8

We move all terms to the left:

(3y-4)(y+2)(y+1)-(3y+5y-6y-8)=0

We add all the numbers together, and all the variables

(3y-4)(y+2)(y+1)-(2y-8)=0

We get rid of parentheses

(3y-4)(y+2)(y+1)-2y+8=0

We multiply parentheses ..

(+3y^2+6y-4y-8)(y+1)-2y+8=0

We move all terms containing y to the left, all other terms to the right

(+3y^2+6y-4y-8)(y+1)-2y=-8

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