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(3y-4)(y+2)(y+1)=3y+5y-6y-8
We move all terms to the left:
(3y-4)(y+2)(y+1)-(3y+5y-6y-8)=0
We add all the numbers together, and all the variables
(3y-4)(y+2)(y+1)-(2y-8)=0
We get rid of parentheses
(3y-4)(y+2)(y+1)-2y+8=0
We multiply parentheses ..
(+3y^2+6y-4y-8)(y+1)-2y+8=0
We move all terms containing y to the left, all other terms to the right
(+3y^2+6y-4y-8)(y+1)-2y=-8
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