(3y-4)+(2y+3)=6y-31

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Solution for (3y-4)+(2y+3)=6y-31 equation: 



(3y-4)+(2y+3)=6y-31

We move all terms to the left:

(3y-4)+(2y+3)-(6y-31)=0

We get rid of parentheses

3y+2y-6y-4+3+31=0

We add all the numbers together, and all the variables

-1y+30=0

We move all terms containing y to the left, all other terms to the right

-y=-30

y=-30/-1

y=+30

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