(3y-5)+(2y)+(3y-5)+(2y)=

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Solution for (3y-5)+(2y)+(3y-5)+(2y)= equation:


Simplifying
(3y + -5) + (2y) + (3y + -5) + (2y) = 0

Reorder the terms:
(-5 + 3y) + (2y) + (3y + -5) + (2y) = 0

Remove parenthesis around (-5 + 3y)
-5 + 3y + (2y) + (3y + -5) + (2y) = 0

Reorder the terms:
-5 + 3y + (2y) + (-5 + 3y) + (2y) = 0

Remove parenthesis around (-5 + 3y)
-5 + 3y + (2y) + -5 + 3y + (2y) = 0

Reorder the terms:
-5 + -5 + 3y + (2y) + 3y + (2y) = 0

Combine like terms: -5 + -5 = -10
-10 + 3y + (2y) + 3y + (2y) = 0

Combine like terms: 3y + (2y) = 5y
-10 + 5y + 3y + (2y) = 0

Combine like terms: 5y + 3y = 8y
-10 + 8y + (2y) = 0

Combine like terms: 8y + (2y) = 10y
-10 + 10y = 0

Solving
-10 + 10y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 10y = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 10y = 0 + 10
10y = 0 + 10

Combine like terms: 0 + 10 = 10
10y = 10

Divide each side by '10'.
y = 1

Simplifying
y = 1

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