(3y-5)+(5y+20)=35

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Solution for (3y-5)+(5y+20)=35 equation: 



(3y-5)+(5y+20)=35

We move all terms to the left:

(3y-5)+(5y+20)-(35)=0

We get rid of parentheses

3y+5y-5+20-35=0

We add all the numbers together, and all the variables

8y-20=0

We move all terms containing y to the left, all other terms to the right

8y=20

y=20/8

y=2+1/2

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