(3y-5)+(5y=20)=135

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Solution for (3y-5)+(5y=20)=135 equation: 



(3y-5)+(5y=20)=135

We move all terms to the left:

(3y-5)+(5y-(20))=0

We get rid of parentheses

3y+5y-5-20=0

We add all the numbers together, and all the variables

8y-25=0

We move all terms containing y to the left, all other terms to the right

8y=25

y=25/8

y=3+1/8

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