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(3y-5)/2+1=y/2+3
We move all terms to the left:
(3y-5)/2+1-(y/2+3)=0
We get rid of parentheses
(3y-5)/2-y/2-3+1=0
We multiply all the terms by the denominator
(3y-5)-y-3*2+1*2=0
We add all the numbers together, and all the variables
-1y+(3y-5)-4=0
We get rid of parentheses
-1y+3y-5-4=0
We add all the numbers together, and all the variables
2y-9=0
We move all terms containing y to the left, all other terms to the right
2y=9
y=9/2
y=4+1/2
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