(3y-6)+y=42

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Solution for (3y-6)+y=42 equation: 



(3y-6)+y=42

We move all terms to the left:

(3y-6)+y-(42)=0

We add all the numbers together, and all the variables

y+(3y-6)-42=0

We get rid of parentheses

y+3y-6-42=0

We add all the numbers together, and all the variables

4y-48=0

We move all terms containing y to the left, all other terms to the right

4y=48

y=48/4

y=12

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