(3y-6)/9=(4-2y)/3

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Solution for (3y-6)/9=(4-2y)/3 equation: 



(3y-6)/9=(4-2y)/3

We move all terms to the left:

(3y-6)/9-((4-2y)/3)=0

We add all the numbers together, and all the variables

(3y-6)/9-((-2y+4)/3)=0

We calculate fractions


3y/()+(-((-2y+4)*9)/()=0



We calculate terms in parentheses: +(-((-2y+4)*9)/(), so:

-((-2y+4)*9)/(

We multiply all the terms by the denominator


-((-2y+4)*9)



We calculate terms in parentheses: -((-2y+4)*9), so:

(-2y+4)*9

We multiply parentheses

-18y+36

Back to the equation:

-(-18y+36)



We get rid of parentheses

18y-36

Back to the equation:

+(18y-36)



We get rid of parentheses

3y/()+18y-36=0

We multiply all the terms by the denominator


3y+18y*()-36*()=0

We add all the numbers together, and all the variables

3y+18y*()=0

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