(3y-7)/(12y)=(1/3)

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Solution for (3y-7)/(12y)=(1/3) equation: 


D( y )

12*y = 0

12*y = 0

12*y = 0

12*y = 0 // : 12

y = 0

y in (-oo:0) U (0:+oo)

(3*y-7)/(12*y) = 1/3 // - 1/3

(3*y-7)/(12*y)-(1/3) = 0

(3*y-7)/(12*y)-1/3 = 0

(3*(3*y-7))/(3*12*y)+(-1*12*y)/(3*12*y) = 0

3*(3*y-7)-1*12*y = 0

-3*y-21 = 0

(-3*y-21)/(3*12*y) = 0

(-3*y-21)/(3*12*y) = 0 // * 3*12*y

-3*y-21 = 0

-3*y-21 = 0 // + 21

-3*y = 21 // : -3

y = 21/(-3)

y = -7

y = -7

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