(3y-7)/12y=1/3

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Solution for (3y-7)/12y=1/3 equation:


y in (-oo:+oo)

y*((3*y-7)/12) = 1/3 // - 1/3

y*((3*y-7)/12)-(1/3) = 0

y*((3*y-7)/12)-1/3 = 0

(y*(3*y-7))/12-1/3 = 0

(3*y*(3*y-7))/(3*12)+(-1*12)/(3*12) = 0

3*y*(3*y-7)-1*12 = 0

9*y^2-21*y-12 = 0

9*y^2-21*y-12 = 0

3*(3*y^2-7*y-4) = 0

3*y^2-7*y-4 = 0

DELTA = (-7)^2-(-4*3*4)

DELTA = 97

DELTA > 0

y = (97^(1/2)+7)/(2*3) or y = (7-97^(1/2))/(2*3)

y = (97^(1/2)+7)/6 or y = (7-97^(1/2))/6

3*(y-((7-97^(1/2))/6))*(y-((97^(1/2)+7)/6)) = 0

(3*(y-((7-97^(1/2))/6))*(y-((97^(1/2)+7)/6)))/(3*12) = 0

(3*(y-((7-97^(1/2))/6))*(y-((97^(1/2)+7)/6)))/(3*12) = 0 // * 3*12

3*(y-((7-97^(1/2))/6))*(y-((97^(1/2)+7)/6)) = 0

( y-((7-97^(1/2))/6) )

y-((7-97^(1/2))/6) = 0 // + (7-97^(1/2))/6

y = (7-97^(1/2))/6

( y-((97^(1/2)+7)/6) )

y-((97^(1/2)+7)/6) = 0 // + (97^(1/2)+7)/6

y = (97^(1/2)+7)/6

y in { (7-97^(1/2))/6, (97^(1/2)+7)/6 }

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