(3y-7+y+3)/2=y+6

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Solution for (3y-7+y+3)/2=y+6 equation: 



(3y-7+y+3)/2=y+6

We move all terms to the left:

(3y-7+y+3)/2-(y+6)=0

We add all the numbers together, and all the variables

(4y-4)/2-(y+6)=0

We get rid of parentheses

(4y-4)/2-y-6=0

We multiply all the terms by the denominator


(4y-4)-y*2-6*2=0

We add all the numbers together, and all the variables

(4y-4)-y*2-12=0

Wy multiply elements

(4y-4)-2y-12=0

We get rid of parentheses

4y-2y-4-12=0

We add all the numbers together, and all the variables

2y-16=0

We move all terms containing y to the left, all other terms to the right

2y=16

y=16/2

y=8

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