(3y=53)(7y-55)

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Solution for (3y=53)(7y-55) equation: 



(3y=53)(7y-55)

We move all terms to the left:

(3y-(53)(7y-55))=0



We calculate terms in parentheses: +(3y-53(7y-55)), so:

3y-53(7y-55)

We multiply parentheses

3y-371y+2915

We add all the numbers together, and all the variables

-368y+2915

Back to the equation:

+(-368y+2915)



We get rid of parentheses

-368y+2915=0

We move all terms containing y to the left, all other terms to the right

-368y=-2915

y=-2915/-368

y=7+339/368

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