(3z+1)(z+2)=

Solution for (3z+1)(z+2)= equation:

Simplifying
(3z + 1)(z + 2) = 0

Reorder the terms:
(1 + 3z)(z + 2) = 0

Reorder the terms:
(1 + 3z)(2 + z) = 0

Multiply (1 + 3z) * (2 + z)
(1(2 + z) + 3z * (2 + z)) = 0
((2 * 1 + z * 1) + 3z * (2 + z)) = 0
((2 + 1z) + 3z * (2 + z)) = 0
(2 + 1z + (2 * 3z + z * 3z)) = 0
(2 + 1z + (6z + 3z2)) = 0

Combine like terms: 1z + 6z = 7z
(2 + 7z + 3z2) = 0

Solving
2 + 7z + 3z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(2 + z)(1 + 3z) = 0

Subproblem 1
Set the factor '(2 + z)' equal to zero and attempt to solve:

Simplifying
2 + z = 0

Solving
2 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + z = 0 + -2

Combine like terms: 2 + -2 = 0
0 + z = 0 + -2
z = 0 + -2

Combine like terms: 0 + -2 = -2
z = -2

Simplifying
z = -2
Subproblem 2
Set the factor '(1 + 3z)' equal to zero and attempt to solve:

Simplifying
1 + 3z = 0

Solving
1 + 3z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3z = 0 + -1
3z = 0 + -1

Combine like terms: 0 + -1 = -1
3z = -1

Divide each side by '3'.
z = -0.3333333333

Simplifying
z = -0.3333333333
Solution
z = {-2, -0.3333333333}