(3z+1)=(5+7z)

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Solution for (3z+1)=(5+7z) equation: 



(3z+1)=(5+7z)

We move all terms to the left:

(3z+1)-((5+7z))=0

We add all the numbers together, and all the variables

(3z+1)-((7z+5))=0

We get rid of parentheses

3z-((7z+5))+1=0



We calculate terms in parentheses: -((7z+5)), so:

(7z+5)

We get rid of parentheses

7z+5

Back to the equation:

-(7z+5)



We get rid of parentheses

3z-7z-5+1=0

We add all the numbers together, and all the variables

-4z-4=0

We move all terms containing z to the left, all other terms to the right

-4z=4

z=4/-4

z=-1

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