(3z+12)+(4z-6)=90

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Solution for (3z+12)+(4z-6)=90 equation:


Simplifying
(3z + 12) + (4z + -6) = 90

Reorder the terms:
(12 + 3z) + (4z + -6) = 90

Remove parenthesis around (12 + 3z)
12 + 3z + (4z + -6) = 90

Reorder the terms:
12 + 3z + (-6 + 4z) = 90

Remove parenthesis around (-6 + 4z)
12 + 3z + -6 + 4z = 90

Reorder the terms:
12 + -6 + 3z + 4z = 90

Combine like terms: 12 + -6 = 6
6 + 3z + 4z = 90

Combine like terms: 3z + 4z = 7z
6 + 7z = 90

Solving
6 + 7z = 90

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 7z = 90 + -6

Combine like terms: 6 + -6 = 0
0 + 7z = 90 + -6
7z = 90 + -6

Combine like terms: 90 + -6 = 84
7z = 84

Divide each side by '7'.
z = 12

Simplifying
z = 12

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