(3z+3)/2=(z+3)/4

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Solution for (3z+3)/2=(z+3)/4 equation: 



(3z+3)/2=(z+3)/4

We move all terms to the left:

(3z+3)/2-((z+3)/4)=0

We calculate fractions


3z/()+(-((z+3)*2)/()=0



We calculate terms in parentheses: +(-((z+3)*2)/(), so:

-((z+3)*2)/(

We multiply all the terms by the denominator


-((z+3)*2)



We calculate terms in parentheses: -((z+3)*2), so:

(z+3)*2

We multiply parentheses

2z+6

Back to the equation:

-(2z+6)



We get rid of parentheses

-2z-6

Back to the equation:

+(-2z-6)



We get rid of parentheses

3z/()-2z-6=0

We multiply all the terms by the denominator


3z-2z*()-6*()=0

We add all the numbers together, and all the variables

3z-2z*()=0

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