(3z+8=)+(z+6=)

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Solution for (3z+8=)+(z+6=) equation: 



(3z+8=)+(z+6=)

We move all terms to the left:

(3z+8-()+(z+6)=0



We calculate terms in parentheses: +(3z+8-()+(z+6), so:

3z+8-()+(z+6

determiningTheFunctionDomain
3z+(z+6+8-()



We calculate terms in parentheses: +(z+6+8-(), so:

z+6+8-(

We add all the numbers together, and all the variables

z

Back to the equation:

+(z)



We add all the numbers together, and all the variables

4z

Back to the equation:

+(4z)



z=0/4

z=0

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