(3z+9)=6(2z-6)

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Solution for (3z+9)=6(2z-6) equation: 



(3z+9)=6(2z-6)

We move all terms to the left:

(3z+9)-(6(2z-6))=0

We get rid of parentheses

3z-(6(2z-6))+9=0



We calculate terms in parentheses: -(6(2z-6)), so:

6(2z-6)

We multiply parentheses

12z-36

Back to the equation:

-(12z-36)



We get rid of parentheses

3z-12z+36+9=0

We add all the numbers together, and all the variables

-9z+45=0

We move all terms containing z to the left, all other terms to the right

-9z=-45

z=-45/-9

z=+5

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