(3z-12)=162

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Solution for (3z-12)=162 equation: 



(3z-12)=162

We move all terms to the left:

(3z-12)-(162)=0

We get rid of parentheses

3z-12-162=0

We add all the numbers together, and all the variables

3z-174=0

We move all terms containing z to the left, all other terms to the right

3z=174

z=174/3

z=58

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