(3z-5)=(2z+2)

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Solution for (3z-5)=(2z+2) equation: 



(3z-5)=(2z+2)

We move all terms to the left:

(3z-5)-((2z+2))=0

We get rid of parentheses

3z-((2z+2))-5=0



We calculate terms in parentheses: -((2z+2)), so:

(2z+2)

We get rid of parentheses

2z+2

Back to the equation:

-(2z+2)



We get rid of parentheses

3z-2z-2-5=0

We add all the numbers together, and all the variables

z-7=0

We move all terms containing z to the left, all other terms to the right

z=7

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