(3z/2)+(1/4)=(7/8)

Solution for (3z/2)+(1/4)=(7/8) equation:

(3z/2)+(1/4)=(7/8)

We move all terms to the left:

(3z/2)+(1/4)-((7/8))=0

We add all the numbers together, and all the variables

(+3z/2)+(+1/4)-((+7/8))=0

We get rid of parentheses

3z/2+1/4-((+7/8))=0

We calculate fractions


768z^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

768z^2/()+2=0

We multiply all the terms by the denominator


768z^2+2*()=0

We add all the numbers together, and all the variables

768z^2=0

a = 768; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·768·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{1536}=0$