(3z/7)-2=-3

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Solution for (3z/7)-2=-3 equation:



(3z/7)-2=-3
We move all terms to the left:
(3z/7)-2-(-3)=0
We add all the numbers together, and all the variables
(+3z/7)-2-(-3)=0
We add all the numbers together, and all the variables
(+3z/7)+1=0
We get rid of parentheses
3z/7+1=0
We multiply all the terms by the denominator
3z+1*7=0
We add all the numbers together, and all the variables
3z+7=0
We move all terms containing z to the left, all other terms to the right
3z=-7
z=-7/3
z=-2+1/3

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