(4(3y+2))=64

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Solution for (4(3y+2))=64 equation: 



(4(3y+2))=64

We move all terms to the left:

(4(3y+2))-(64)=0



We calculate terms in parentheses: +(4(3y+2)), so:

4(3y+2)

We multiply parentheses

12y+8

Back to the equation:

+(12y+8)



We get rid of parentheses

12y+8-64=0

We add all the numbers together, and all the variables

12y-56=0

We move all terms containing y to the left, all other terms to the right

12y=56

y=56/12

y=4+2/3

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