(4(n+3))/5=n-3

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Solution for (4(n+3))/5=n-3 equation: 



(4(n+3))/5=n-3

We move all terms to the left:

(4(n+3))/5-(n-3)=0

We get rid of parentheses

(4(n+3))/5-n+3=0

We multiply all the terms by the denominator


(4(n+3))-n*5+3*5=0



We calculate terms in parentheses: +(4(n+3)), so:

4(n+3)

We multiply parentheses

4n+12

Back to the equation:

+(4n+12)



We add all the numbers together, and all the variables

(4n+12)-n*5+15=0

Wy multiply elements

(4n+12)-5n+15=0

We get rid of parentheses

4n-5n+12+15=0

We add all the numbers together, and all the variables

-1n+27=0

We move all terms containing n to the left, all other terms to the right

-n=-27

n=-27/-1

n=+27

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