(4(x+4)/8)=3x-3

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Solution for (4(x+4)/8)=3x-3 equation: 



(4(x+4)/8)=3x-3

We move all terms to the left:

(4(x+4)/8)-(3x-3)=0

We get rid of parentheses

(4(x+4)/8)-3x+3=0

We multiply all the terms by the denominator


(4(x+4)-3x*8)+3*8)=0



We calculate terms in parentheses: +(4(x+4)-3x*8), so:

4(x+4)-3x*8

We multiply parentheses

4x-3x*8+16

Wy multiply elements

4x-24x+16

We add all the numbers together, and all the variables

-20x+16

Back to the equation:

+(-20x+16)



We add all the numbers together, and all the variables

(-20x+16)=0

We get rid of parentheses

-20x+16=0

We move all terms containing x to the left, all other terms to the right

-20x=-16

x=-16/-20

x=4/5

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