(4(x-7)-7)/3)=15

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Solution for (4(x-7)-7)/3)=15 equation: 



(4(x-7)-7)/3)=15

We move all terms to the left:

(4(x-7)-7)/3)-(15)=0

We multiply all the terms by the denominator


(4(x-7)-7)=0



We calculate terms in parentheses: +(4(x-7)-7), so:

4(x-7)-7

We multiply parentheses

4x-28-7

We add all the numbers together, and all the variables

4x-35

Back to the equation:

+(4x-35)



We get rid of parentheses

4x-35=0

We move all terms containing x to the left, all other terms to the right

4x=35

x=35/4

x=8+3/4

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