(4)/(2x-1)=(3)/(3-x)

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Solution for (4)/(2x-1)=(3)/(3-x) equation:



(4)/(2x-1)=(3)/(3-x)
We move all terms to the left:
(4)/(2x-1)-((3)/(3-x))=0
Domain of the equation: (2x-1)!=0
We move all terms containing x to the left, all other terms to the right
2x!=1
x!=1/2
x!=1/2
x∈R
Domain of the equation: (3-x))!=0
We move all terms containing x to the left, all other terms to the right
-x)!=-3
x!=-3/1
x!=-3
x∈R
We add all the numbers together, and all the variables
4/(2x-1)-(3/(-1x+3))=0
We calculate fractions
(-4x)/((2x-1)*(-1x+3)))+(-(3*(2x-1))/((2x-1)*(-1x+3)))=0
We calculate terms in parentheses: -(3*(2x-1))/((2x-1)*(-1x+3))), so:
3*(2x-1))/((2x-1)*(-1x+3))
We multiply all the terms by the denominator
3*(2x-1))
We multiply parentheses
6x+
We add all the numbers together, and all the variables
6x
Back to the equation:
-(6x)
We add all the numbers together, and all the variables
-6x+(-4x)/((2x-1)*(-1x+3)))+(=0
We multiply all the terms by the denominator
-6x*((2x-1)*(-1x+3)))+(+(-4x)=0
We get rid of parentheses
-6x*((2x-1)*(-1x+3)))+(-4x=0
We add all the numbers together, and all the variables
-4x-6x*((2x-1)*(-1x+3)))+(=0

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