(4)/(x-1)+(6)/(3x+1)=(15)/(3x+1)

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Solution for (4)/(x-1)+(6)/(3x+1)=(15)/(3x+1) equation:


D( x )

3*x+1 = 0

x-1 = 0

3*x+1 = 0

3*x+1 = 0

3*x+1 = 0 // - 1

3*x = -1 // : 3

x = -1/3

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-1/3) U (-1/3:1) U (1:+oo)

4/(x-1)+6/(3*x+1) = 15/(3*x+1) // - 15/(3*x+1)

4/(x-1)+6/(3*x+1)-(15/(3*x+1)) = 0

4/(x-1)+6/(3*x+1)-15*(3*x+1)^-1 = 0

4/(x-1)+6/(3*x+1)-15/(3*x+1) = 0

(4*(3*x+1))/((x-1)*(3*x+1))+(6*(x-1))/((x-1)*(3*x+1))+(-15*(x-1))/((x-1)*(3*x+1)) = 0

4*(3*x+1)+6*(x-1)-15*(x-1) = 0

18*x-15*x-2+15 = 0

3*x+13 = 0

(3*x+13)/((x-1)*(3*x+1)) = 0

(3*x+13)/((x-1)*(3*x+1)) = 0 // * (x-1)*(3*x+1)

3*x+13 = 0

3*x+13 = 0 // - 13

3*x = -13 // : 3

x = -13/3

x = -13/3

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