(4)/(x-2)+3=(x+2)/(x-2)

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Solution for (4)/(x-2)+3=(x+2)/(x-2) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

4/(x-2)+3 = (x+2)/(x-2) // - (x+2)/(x-2)

4/(x-2)-((x+2)/(x-2))+3 = 0

4/(x-2)+(-1*(x+2))/(x-2)+3 = 0

4/(x-2)+(-1*(x+2))/(x-2)+(3*(x-2))/(x-2) = 0

3*(x-2)-1*(x+2)+4 = 0

3*x-x-6+2 = 0

2*x-4 = 0

(2*x-4)/(x-2) = 0

(2*x-4)/(x-2) = 0 // * x-2

2*x-4 = 0

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

x in { 2} 

x belongs to the empty set

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