(4)/(x-4)=(x)/(x-4)-(4)/(3)

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Solution for (4)/(x-4)=(x)/(x-4)-(4)/(3) equation: 


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

4/(x-4) = x/(x-4)-(4/3) // - x/(x-4)-(4/3)

4/(x-4)-(x/(x-4))+4/3 = 0

4/(x-4)+(-1*x)/(x-4)+4/3 = 0

(3*4)/(3*(x-4))+(-1*3*x)/(3*(x-4))+(4*(x-4))/(3*(x-4)) = 0

4*(x-4)-1*3*x+3*4 = 0

4*x-3*x-16+12 = 0

x-4 = 0

(x-4)/(3*(x-4)) = 0

(x-4)/(3*(x-4)) = 0 // * 3*(x-4)

x-4 = 0

x-4 = 0 // + 4

x = 4

x in { 4} 

x belongs to the empty set

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