(4)1z+3(z-1)=36

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Solution for (4)1z+3(z-1)=36 equation: 



(4)1z+3(z-1)=36

We move all terms to the left:

(4)1z+3(z-1)-(36)=0

We multiply parentheses

41z+3z-3-36=0

We add all the numbers together, and all the variables

44z-39=0

We move all terms containing z to the left, all other terms to the right

44z=39

z=39/44

z=39/44

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