(4)=(3/4)m-6

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Solution for (4)=(3/4)m-6 equation: 



(4)=(3/4)m-6

We move all terms to the left:

(4)-((3/4)m-6)=0



Domain of the equation: 4)m-6)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

-((+3/4)m-6)+4=0

We multiply all the terms by the denominator


-((+3+4*4)m-6)=0



We calculate terms in parentheses: -((+3+4*4)m-6), so:

(+3+4*4)m-6

We add all the numbers together, and all the variables

19m-6

Back to the equation:

-(19m-6)



We get rid of parentheses

-19m+6=0

We move all terms containing m to the left, all other terms to the right

-19m=-6

m=-6/-19

m=6/19

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