(4*(c+3))-(3*(c+2))=0

Solution for (4*(c+3))-(3*(c+2))=0 equation:

Simplifying
(4(c + 3)) + -1(3(c + 2)) = 0

Reorder the terms:
(4(3 + c)) + -1(3(c + 2)) = 0
((3 * 4 + c * 4)) + -1(3(c + 2)) = 0
((12 + 4c)) + -1(3(c + 2)) = 0
(12 + 4c) + -1(3(c + 2)) = 0

Remove parenthesis around (12 + 4c)
12 + 4c + -1(3(c + 2)) = 0

Reorder the terms:
12 + 4c + -1(3(2 + c)) = 0
12 + 4c + -1((2 * 3 + c * 3)) = 0
12 + 4c + -1((6 + 3c)) = 0
12 + 4c + (6 * -1 + 3c * -1) = 0
12 + 4c + (-6 + -3c) = 0

Reorder the terms:
12 + -6 + 4c + -3c = 0

Combine like terms: 12 + -6 = 6
6 + 4c + -3c = 0

Combine like terms: 4c + -3c = 1c
6 + 1c = 0

Solving
6 + 1c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 1c = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 1c = 0 + -6
1c = 0 + -6

Combine like terms: 0 + -6 = -6
1c = -6

Divide each side by '1'.
c = -6

Simplifying
c = -6