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(4x+3)(x*3-2)=576
We move all terms to the left:
(4x+3)(x*3-2)-(576)=0
We multiply parentheses ..
(+12x^2-8x+9x-6)-576=0
We get rid of parentheses
12x^2-8x+9x-6-576=0
We add all the numbers together, and all the variables
12x^2+x-582=0
a = 12; b = 1; c = -582;
Δ = b2-4ac
Δ = 12-4·12·(-582)
Δ = 27937
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{27937}}{2*12}=\frac{-1-\sqrt{27937}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{27937}}{2*12}=\frac{-1+\sqrt{27937}}{24} $
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