(4+2)+(1k+4k)=38

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Solution for (4+2)+(1k+4k)=38 equation: 



(4+2)+(1k+4k)=38

We move all terms to the left:

(4+2)+(1k+4k)-(38)=0

determiningTheFunctionDomain
(1k+4k)-38+(4+2)=0

We add all the numbers together, and all the variables

(+5k)-38+6=0

We add all the numbers together, and all the variables

(+5k)-32=0

We get rid of parentheses

5k-32=0

We move all terms containing k to the left, all other terms to the right

5k=32

k=32/5

k=6+2/5

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