(4+2)+5=4+(x+5)

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Solution for (4+2)+5=4+(x+5) equation: 



(4+2)+5=4+(x+5)

We move all terms to the left:

(4+2)+5-(4+(x+5))=0

We add all the numbers together, and all the variables

-(4+(x+5))+5+6=0

We add all the numbers together, and all the variables

-(4+(x+5))+11=0



We calculate terms in parentheses: -(4+(x+5)), so:

4+(x+5)

determiningTheFunctionDomain
(x+5)+4

We get rid of parentheses

x+5+4

We add all the numbers together, and all the variables

x+9

Back to the equation:

-(x+9)



We get rid of parentheses

-x-9+11=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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