(4+2b)-(3-3b)=

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Solution for (4+2b)-(3-3b)= equation: 



(4+2b)-(3-3b)=

We move all terms to the left:

(4+2b)-(3-3b)-()=0

We add all the numbers together, and all the variables

(2b+4)-(-3b+3)-()=0

We add all the numbers together, and all the variables

(2b+4)-(-3b+3)=0

We get rid of parentheses

2b+3b+4-3=0

We add all the numbers together, and all the variables

5b+1=0

We move all terms containing b to the left, all other terms to the right

5b=-1

b=-1/5

b=-1/5

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