(4+2i)+(2-3i)=i

Solution for (4+2i)+(2-3i)=i equation:

Simplifying
(4 + 2i) + (2 + -3i) = i

Remove parenthesis around (4 + 2i)
4 + 2i + (2 + -3i) = i

Remove parenthesis around (2 + -3i)
4 + 2i + 2 + -3i = i

Reorder the terms:
4 + 2 + 2i + -3i = i

Combine like terms: 4 + 2 = 6
6 + 2i + -3i = i

Combine like terms: 2i + -3i = -1i
6 + -1i = i

Solving
6 + -1i = i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1i' to each side of the equation.
6 + -1i + -1i = i + -1i

Combine like terms: -1i + -1i = -2i
6 + -2i = i + -1i

Combine like terms: i + -1i = 0
6 + -2i = 0

Add '-6' to each side of the equation.
6 + -6 + -2i = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -2i = 0 + -6
-2i = 0 + -6

Combine like terms: 0 + -6 = -6
-2i = -6

Divide each side by '-2'.
i = 3

Simplifying
i = 3