(4+3i)(x+Yi)=(12-3i)

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Solution for (4+3i)(x+Yi)=(12-3i) equation:


Simplifying
(4 + 3i)(x + Yi) = (12 + -3i)

Reorder the terms:
(4 + 3i)(iY + x) = (12 + -3i)

Multiply (4 + 3i) * (iY + x)
(4(iY + x) + 3i * (iY + x)) = (12 + -3i)
((iY * 4 + x * 4) + 3i * (iY + x)) = (12 + -3i)
((4iY + 4x) + 3i * (iY + x)) = (12 + -3i)
(4iY + 4x + (iY * 3i + x * 3i)) = (12 + -3i)

Reorder the terms:
(4iY + 4x + (3ix + 3i2Y)) = (12 + -3i)
(4iY + 4x + (3ix + 3i2Y)) = (12 + -3i)

Reorder the terms:
(4iY + 3ix + 3i2Y + 4x) = (12 + -3i)
(4iY + 3ix + 3i2Y + 4x) = (12 + -3i)

Remove parenthesis around (12 + -3i)
4iY + 3ix + 3i2Y + 4x = 12 + -3i

Solving
4iY + 3ix + 3i2Y + 4x = 12 + -3i

Solving for variable 'i'.

Reorder the terms:
-12 + 3i + 4iY + 3ix + 3i2Y + 4x = 12 + -3i + -12 + 3i

Reorder the terms:
-12 + 3i + 4iY + 3ix + 3i2Y + 4x = 12 + -12 + -3i + 3i

Combine like terms: 12 + -12 = 0
-12 + 3i + 4iY + 3ix + 3i2Y + 4x = 0 + -3i + 3i
-12 + 3i + 4iY + 3ix + 3i2Y + 4x = -3i + 3i

Combine like terms: -3i + 3i = 0
-12 + 3i + 4iY + 3ix + 3i2Y + 4x = 0

The solution to this equation could not be determined.

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