(4+3i)/(2-2i)=

Solution for (4+3i)/(2-2i)= equation:

(4+3i)/(2-2i)=

We move all terms to the left:

(4+3i)/(2-2i)-()=0


Domain of the equation: (2-2i)!=0

We move all terms containing i to the left, all other terms to the right

-2i!=-2

i!=-2/-2

i!=1

i∈R


We add all the numbers together, and all the variables

(3i+4)/(-2i+2)-()=0

We add all the numbers together, and all the variables

(3i+4)/(-2i+2)=0

We multiply all the terms by the denominator


(3i+4)=0

We get rid of parentheses

3i+4=0

We move all terms containing i to the left, all other terms to the right

3i=-4

i=-4/3

i=-1+1/3