(4+3y)+(2+2n)=

Solution for (4+3y)+(2+2n)= equation:

Simplifying
(4 + 3y) + (2 + 2n) = 0

Remove parenthesis around (4 + 3y)
4 + 3y + (2 + 2n) = 0

Remove parenthesis around (2 + 2n)
4 + 3y + 2 + 2n = 0

Reorder the terms:
4 + 2 + 2n + 3y = 0

Combine like terms: 4 + 2 = 6
6 + 2n + 3y = 0

Solving
6 + 2n + 3y = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 2n + -6 + 3y = 0 + -6

Reorder the terms:
6 + -6 + 2n + 3y = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 2n + 3y = 0 + -6
2n + 3y = 0 + -6

Combine like terms: 0 + -6 = -6
2n + 3y = -6

Add '-3y' to each side of the equation.
2n + 3y + -3y = -6 + -3y

Combine like terms: 3y + -3y = 0
2n + 0 = -6 + -3y
2n = -6 + -3y

Divide each side by '2'.
n = -3 + -1.5y

Simplifying
n = -3 + -1.5y