(4+4b)+(1+5c)=

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Solution for (4+4b)+(1+5c)= equation:


Simplifying
(4 + 4b) + (1 + 5c) = 0

Remove parenthesis around (4 + 4b)
4 + 4b + (1 + 5c) = 0

Remove parenthesis around (1 + 5c)
4 + 4b + 1 + 5c = 0

Reorder the terms:
4 + 1 + 4b + 5c = 0

Combine like terms: 4 + 1 = 5
5 + 4b + 5c = 0

Solving
5 + 4b + 5c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + 4b + -5 + 5c = 0 + -5

Reorder the terms:
5 + -5 + 4b + 5c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 4b + 5c = 0 + -5
4b + 5c = 0 + -5

Combine like terms: 0 + -5 = -5
4b + 5c = -5

Add '-5c' to each side of the equation.
4b + 5c + -5c = -5 + -5c

Combine like terms: 5c + -5c = 0
4b + 0 = -5 + -5c
4b = -5 + -5c

Divide each side by '4'.
b = -1.25 + -1.25c

Simplifying
b = -1.25 + -1.25c

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