(4+5y)/2=4/(2+5y)

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Solution for (4+5y)/2=4/(2+5y) equation:


D( y )

5*y+2 = 0

5*y+2 = 0

5*y+2 = 0

5*y+2 = 0 // - 2

5*y = -2 // : 5

y = -2/5

y in (-oo:-2/5) U (-2/5:+oo)

(5*y+4)/2 = 4/(5*y+2) // - 4/(5*y+2)

(5*y+4)/2-(4/(5*y+2)) = 0

(5*y+4)/2-4*(5*y+2)^-1 = 0

(5*y+4)/2-4/(5*y+2) = 0

((5*y+4)*(5*y+2))/(2*(5*y+2))+(-4*2)/(2*(5*y+2)) = 0

(5*y+4)*(5*y+2)-4*2 = 0

25*y^2+30*y = 0

25*y^2+30*y = 0

5*y*(5*y+6) = 0

5*y+6 = 0 // - 6

5*y = -6 // : 5

y = -6/5

5*y*(y+6/5) = 0

(5*y*(y+6/5))/(2*(5*y+2)) = 0

(5*y*(y+6/5))/(2*(5*y+2)) = 0 // * 2*(5*y+2)

5*y*(y+6/5) = 0

( 5*y )

5*y = 0 // : 5

y = 0

( y+6/5 )

y+6/5 = 0 // - 6/5

y = -6/5

y in { 0, -6/5 }

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