(4+8i)(10+5i)=0

Solution for (4+8i)(10+5i)=0 equation:

(4+8i)(10+5i)=0

We add all the numbers together, and all the variables

(8i+4)(5i+10)=0

We multiply parentheses ..

(+40i^2+80i+20i+40)=0

We get rid of parentheses

40i^2+80i+20i+40=0

We add all the numbers together, and all the variables

40i^2+100i+40=0

a = 40; b = 100; c = +40;
Δ = b2-4ac
Δ = 1002-4·40·40
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-60}{2*40}=\frac{-160}{80}
=-2
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+60}{2*40}=\frac{-40}{80}
=-1/2
$