(4+8s)=(2-3s)=3(s+6)

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Solution for (4+8s)=(2-3s)=3(s+6) equation: 



(4+8s)=(2-3s)=3(s+6)

We move all terms to the left:

(4+8s)-((2-3s))=0

We add all the numbers together, and all the variables

(8s+4)-((-3s+2))=0

We get rid of parentheses

8s-((-3s+2))+4=0



We calculate terms in parentheses: -((-3s+2)), so:

(-3s+2)

We get rid of parentheses

-3s+2

Back to the equation:

-(-3s+2)



We get rid of parentheses

8s+3s-2+4=0

We add all the numbers together, and all the variables

11s+2=0

We move all terms containing s to the left, all other terms to the right

11s=-2

s=-2/11

s=-2/11

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